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The median is the middle number in a list of numbers.

To find the median, you must first put the numbers in numerical order.

6.0, 6.2, 6.2, 6.7, 7.6, 8.1

Then, since there is an even amount of numbers in this sequence, you need to find the two middle numbers (If there were an odd amount of numbers, you would just choose the number directly in the middle to be your median).

6.2 and 6.7

You need to now find the number between these two to get the median. So...

6.7-6.2= 0.5 -----> There is a difference of 0.5 between the two numbers.

0.5/2= 0.25 ----> Divide the difference to get the halfway point between the numbers

6.2+0.25=6.24 ----> Add the halfway point to the smaller number to get your median.

Median = 6.24

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Q: What is the median of 7.6 6.7 8.1 6.2 6.0 6.2?

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It is 82

75, which is half way between the two middle numbers.

The median is 82, the middle value.

One possible set is 62, 62, 75, 76 and 82

65 is the median,

It is 76.

step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.

Then that number will be the median. For example, if your set is 4, 4, 19, 20, 23, 23, 23, 43, 62, 76 and 89, then the second 23 is the middle number, and so it is the Median.

The median is 94.

Yes, it is OK.

I guess you mean: What is the median of the numbers 71, 67, 67, 72, 76, 73, 68, 72, 72? (because adding the numbers would yield a single number). The median is the middle number when the numbers are listed in order. Listing in order: 71, 67, 67, 72, 76, 73, 68, 72, 72 ⇒ 67, 67, 68, 71, 72, 72, 72, 73, 76 There are 9 numbers, so the middle number is the 5th one which is 72. If there had been an even number of numbers, there is no middle one so the median is the mean average of the middle two. Example: If there had been no 76, so the list contained: 67, 67, 68, 71, 72, 72, 72, 73 then there would be 8 numbers, so the median would be the mean average of the 4th and 5th numbers, namely: (71 + 72) ÷ 2 = 71.5

The median is 78.

9+67 = 76

14 times 56 60 61 62 63 64 65 66 67 68 69 76 86 96

52.5

The greatest common factor of the numbers 76 and 62 is 2.

6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96 so 19

62 multiplied by 0.76

76% of 60 = 45.6

6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96. 20 sixes in total.

20 x 6's which are 6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96.

6 16 26 36 46 56 60 61 62 63 64 65 66 67 68 69 76 86 96 20 6's

The median is 84.

67 + 9 = 76

6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96. Total 20.